RRB JE Merit Index Formula

The Railway Recruitment Board (RRB) uses a standardized Merit Index to rank candidates across different exam sessions and technical disciplines for Junior Engineer posts.

The Merit Index Formula

Merit Index=Sq+(StSq)×MMqMtMqMerit\ Index = S_q + (S_t - S_q) \times \frac{M - M_q}{M_t - M_q}

Variable Definitions

MM:

Marks obtained by the candidate (Actual raw marks for single-session, or Normalized marks for multi-session).

MqM_q:

The qualifying marks for the General category candidate in the specific paper (set at 40).

MtM_t:

The mean marks of the top 0.1% or top 10 candidates (whichever is higher) in that paper.

SqS_q:

Fixed score assigned to qualifying marks (350).

StS_t:

Fixed score assigned to top marks (900).

How it works for 2026

For the 2026 recruitment cycle, the Merit Index serves as a common denominator. Since different engineering branches (Civil, Mechanical, Electrical, etc.) take different papers, the Index allows RRB to create a unified merit list for posts that accept multiple disciplines.

Important Note on Normalization:

If the exam is conducted in multiple shifts for a single group, the raw marks are first normalized using the standard RRB normalization formula before being plugged into the M variable above.

Official Resources

Candidates are advised to monitor their respective regional board websites for the final merit list and cut-off scores:

Last updated for the RRB JE 2026 Recruitment Notification. Formula based on the official Railway Recruitment Board Gazette.